document.write( "Question 240710: for problems 7-9 solve the system of equations using addition to eliminate one variable. if the system has no solution, indicate that it is inconsistent. if it has infinite solutions, indicate that it is inconsistent. if it has infinite that it is dependent. if the system has a solution check your answer.\r
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document.write( "4x-3y=17
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document.write( "5x+y=7\r
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document.write( "check (if possible) \n" );
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Algebra.Com's Answer #176355 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "--------- \n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "--------- \n" ); document.write( "Start by rewritting equation 2. Since Y is by itself, solve for Y \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you can plug (7-5X) into equation 1 for Y \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find Y, plug 2 in for X into the rewritten equation 2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Chesk Solution: \n" ); document.write( "--------- \n" ); document.write( "Using X = 2 and Y = -3, solve equation 1 \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |