document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=240711>Question 240711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rectangle perimeter is 240 yards.  Length equals width plus 16 yards.  What are the dimensions?  What is the area?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176344 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's first show the width by using x. No w we can show the length by using x+16. We know the perimeter so we can form and equation. <BR>\n" );
document.write( "x+x+(x+16)+(x+16)=240 yds Combine like terms gives us:<BR>\n" );
document.write( "4x+32=240 Subtract 32 from both sides gives us:<BR>\n" );
document.write( "4x=208    Divide 4 into both sides gives us:<BR>\n" );
document.write( "x=52      OK, now we know:<BR>\n" );
document.write( "width is 52 yds Length is 68 yds. <BR>\n" );
document.write( "I'll let you figure out the area. <BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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