document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=240619>Question 240619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a nurse mix 15 liters of a 10% solution of s drug with som 60% solution to get a 20% MIXTURE. how many liters of the 60% solution will be needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176317 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .60x+.10*15=.20(15+x)<BR>\n" );
document.write( ".60x+1.5=3+.20x<BR>\n" );
document.write( ".60x-.20x=3-1.5<BR>\n" );
document.write( ".40x=1.5<BR>\n" );
document.write( "x=1.5/.4<BR>\n" );
document.write( "x=3.75 liters of 60% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".60*3.75+.10*15=.20(15+3.75)<BR>\n" );
document.write( "2.25+1.5=.20*18.75<BR>\n" );
document.write( "3.75=3.75\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );