document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=240653>Question 240653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 5/4. One number is 1/2 of the other. Find the<BR>\n" );
document.write( "product of these two numbers.\r<BR>\n" );
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document.write( "A. 25/72; B. 25/63; C. 5/8; D. 5/6; E. none </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176313 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 5/4\r<BR>\n" );
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document.write( "x = .5*y\r<BR>\n" );
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document.write( "this makes:\r<BR>\n" );
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document.write( "y = 2*x\r<BR>\n" );
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document.write( "substituting in original equation gets:\r<BR>\n" );
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document.write( "x + 2*x = 5/4\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "3*x = 5/4\r<BR>\n" );
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document.write( "divide both sides by 3 to get:\r<BR>\n" );
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document.write( "x = 5/12\r<BR>\n" );
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document.write( "y = 2x so:\r<BR>\n" );
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document.write( "y = 5/6\r<BR>\n" );
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document.write( "substitute in original equation of x + y = 5/12 to get:\r<BR>\n" );
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document.write( "5/12 + 5/6 = 5/12 + 10/12 = 15/12 = 5/4\r<BR>\n" );
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document.write( "since x = 5/12 and y = 5/6, the product of the two numbers is:\r<BR>\n" );
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document.write( "5/12 * 5/6 = 25/72\r<BR>\n" );
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document.write( "that would be selection A. </SPAN>\n" );
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