document.write( "Question 240662: One car traveling 40 Km/hr left a certain place 4 hours later than another car traveling in the same direction at the rate of 30 km/hr. In how many hours will the faster car overtake the other? \n" ); document.write( "
Algebra.Com's Answer #176302 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=30T \n" ); document.write( "D=40(T-4) \n" ); document.write( "SEEING AS THE 2 DISTANCES ARE THE SAME THEN: \n" ); document.write( "30T=40(T-4) \n" ); document.write( "30T=40T-160 \n" ); document.write( "30T-40T=160 \n" ); document.write( "-10T=-160 \n" ); document.write( "T=-160/-10 \n" ); document.write( "T=16 HOURS THEY WILL MEET. \n" ); document.write( "PROOF: \n" ); document.write( "30*16=40(16-4) \n" ); document.write( "480=40*12 \n" ); document.write( "480=480 \n" ); document.write( " |