document.write( "Question 240559: Solve: 2log(base4)x+log(base4)3=log(base4)x-log(base4)2
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Algebra.Com's Answer #176294 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"2%2Alog%284%2Cx%29%2Blog%284%2C3%29=log%284%2Cx%29-log%284%2C2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2Cx%5E2%29%2Blog%284%2C3%29=log%284%2Cx%29-log%284%2C2%29\"
\n" ); document.write( "\"log%284%2C3x%5E2%29=log%284%2Cx%2F2%29\"
\n" ); document.write( "\"3x%5E2=x%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 2:
\n" ); document.write( "\"6x%5E2+=x\"
\n" ); document.write( "\"6x%5E2-x=0\"\r
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\n" ); document.write( "\n" ); document.write( "Factor the x:
\n" ); document.write( "\"x%286x-1%29=0\"
\n" ); document.write( "There are two solutions:
\n" ); document.write( "x=0 NOTE: THIS ANSWER MUST BE REJECTED, SINCE log(0) is UNDEFINED!!\r
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\n" ); document.write( "\n" ); document.write( "6x-1=0
\n" ); document.write( "6x=1
\n" ); document.write( "x=1/6 This one seems to work!!\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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