document.write( "Question 240634: Solve.
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document.write( "(x+2)(x-11)(x+1)>0
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document.write( "The solution set is {x|___} \n" );
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Algebra.Com's Answer #176274 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Are you allowed to use a graphing calculator or graphing techniques???\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If so, then sketch y=(x+2)(x-11)(x+1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This graph has zeros at x=-2, x=11, and x=-1. Sketch the graph using x values (based upon the zeros that you just found!) from x=-5 to x = 15. Values of y must be larger, but you can try using values from -100 to 100. I'll use the algebra.com calculator and see what it looks like:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, since you are solving the inequality (x+2)(x-11)(x+1)>0, you need to find all values of x for which the graph y=(x+2)(x-11)(x+1) are ABOVE the x axis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This would be values of x from -2 to -1 or values of x from 11 to infinity.\r \n" ); document.write( "\n" ); document.write( "{x|-2 < x <-1} U {x|x > 11} \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired \n" ); document.write( "Seminole State College of Florida \n" ); document.write( " |