document.write( "Question 240512: I need to solve the following word problem using the system of linear equations in two variables. The word problem I am having trouble with is:\r
\n" ); document.write( "\n" ); document.write( "Traveling with the current, a canoe can go 48 miles in 4 hours. traveling against the current, it takes 6 hours to go the same distance. find the speed of the canoe in still water.\r
\n" ); document.write( "\n" ); document.write( "I came up with the following linear equations:
\n" ); document.write( "12=x+y for speed of canoe with current
\n" ); document.write( "8=x-y for speed of canoe against current\r
\n" ); document.write( "\n" ); document.write( "I solved for each variable and came up with x=10, y=2.\r
\n" ); document.write( "\n" ); document.write( "My question is which one is the correct answer for finding the speed of the canoe in still water? My thought is it is x=10.\r
\n" ); document.write( "\n" ); document.write( "Please help
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Algebra.Com's Answer #176214 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT OR R=D/T
\n" ); document.write( "R=48/4=12 MPH WITH THE CURRENT.
\n" ); document.write( "R=48/6=8 MPH AGAINST THE CURRENT
\n" ); document.write( "(12-8)/2=4/2=2 MPH IS THE RATE OF THE CURRENT.
\n" ); document.write( "PROOF:
\n" ); document.write( "12-2=10 MPH SPEED OF THE CANOE IN STILL WATER.
\n" ); document.write( "8+2=10 DITTO.
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