document.write( "Question 30879: Factor completely
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document.write( "2x^2 + 16x + 32
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document.write( "x^3 + 3x^2 + x + 3
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document.write( "3x^2 + 6x - 24 \n" );
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Algebra.Com's Answer #17620 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "You need to find a factor of this ie a value of x that makes the whole thing zero. Since all the terms are positive, then x must be a negative value, to make the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As to the value of x, well this is trial and error to find, but looking at the equation, the value -3 does jump out. Put x=-3 into the expression and you do get zero. So, x+3 is a factor.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You now need to divide this into the cubic expression and then factorise the resulting quadratic, if possible. Having done this for you, the final answer is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Actually, there is a simpler method for this cubic: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can see that both halves have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Third example looks to be like the first.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |