document.write( "Question 30879: Factor completely
\n" ); document.write( "2x^2 + 16x + 32
\n" ); document.write( "x^3 + 3x^2 + x + 3
\n" ); document.write( "3x^2 + 6x - 24
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Algebra.Com's Answer #17620 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"+2x%5E2+%2B+16x+%2B+32+\"
\n" ); document.write( "\"+2%28x%5E2+%2B+8x+%2B+16%29+\"
\n" ); document.write( "\"+2%28x%2B4%29%28x%2B4%29+\"
\n" ); document.write( "\"+2%28x%2B4%29%5E2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+x%5E3+%2B+3x%5E2+%2B+x+%2B+3+\"
\n" ); document.write( "You need to find a factor of this ie a value of x that makes the whole thing zero. Since all the terms are positive, then x must be a negative value, to make the \"x%5E3\" and x negative.\r
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\n" ); document.write( "\n" ); document.write( "As to the value of x, well this is trial and error to find, but looking at the equation, the value -3 does jump out. Put x=-3 into the expression and you do get zero. So, x+3 is a factor.\r
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\n" ); document.write( "\n" ); document.write( "You now need to divide this into the cubic expression and then factorise the resulting quadratic, if possible. Having done this for you, the final answer is \"%28x%2B3%29%28x%5E2%2B1%29\". So try it.\r
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\n" ); document.write( "\n" ); document.write( "Actually, there is a simpler method for this cubic: \"+x%5E3+%2B+3x%5E2+%2B+x+%2B+3+\" written as \"+x%5E3+%2B+x+%2B+3x%5E2+%2B+3+\". Look the 2 sets of 2 terms and factorise each of those:\r
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\n" ); document.write( "\n" ); document.write( "\"+%28x%5E3+%2B+x%29+%2B+%283x%5E2+%2B+3%29+\"
\n" ); document.write( "\"+x%28x%5E2+%2B+1%29+%2B+3%28x%5E2+%2B+1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "You can see that both halves have \"x%5E2%2B1\", so we can factorise again, as \"+%28x%5E2+%2B+1%29%28x+%2B+3%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Third example looks to be like the first.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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