document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30875>Question 30875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 24 foot long piece of pipe is cut into three pieces. The first piece is twice as long as the second piece, and the third piece is 6 feet longer than the second piece. Find the length of each piece. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17617 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=length of second piece.\r<BR>\n" );
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document.write( "So first piece is twice this length --> 2x<BR>\n" );
document.write( "and third piece is 6 feet longer than second --> x+6\r<BR>\n" );
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document.write( "Together we have 2x + x + x+6 = 24<BR>\n" );
document.write( "4x + 6 = 24<BR>\n" );
document.write( "4x = 18<BR>\n" );
document.write( "x = 18/4<BR>\n" );
document.write( "x = 4.5 feet\r<BR>\n" );
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document.write( "So first pice = 9 feet<BR>\n" );
document.write( "second piece = 4.5 feet<BR>\n" );
document.write( "third pice = 10.5 feet\r<BR>\n" );
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document.write( "which add up to 24 feet.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
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