document.write( "Question 30872: write an equation that represents the data in the table.\r
\n" ); document.write( "\n" ); document.write( "x|0|-2|-4|-6|-8
\n" ); document.write( "y|-4|-10|-16|-22|-28
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Algebra.Com's Answer #17616 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
there are 5 terms here, numbered 1,2,3,4 and 5.\r
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\n" ); document.write( "\n" ); document.write( "Look at the difference between the x-terms... a difference of 2, well -2 to be exact.\r
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\n" ); document.write( "\n" ); document.write( "And look at the difference between the y-values: 6... well -6 to be exact.\r
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\n" ); document.write( "\n" ); document.write( "This is a \"three-times table\" since as one variable changes, the other changes by 3 times that. So we have y=3x.\r
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\n" ); document.write( "\n" ); document.write( "Now, y=3x is THE 3-times table ie 3,6,9,12,15,18, etc. We have another 3-times table, \"shifted\" from this. To find the shift, we need to just pick one value of x, so pick an easy one. Namely x=0.\r
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\n" ); document.write( "\n" ); document.write( "when x=0, y=3x becomes y=0 too. We need y to be -4, so we need to subtract 4 from 0 to get the -4. \r
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\n" ); document.write( "\n" ); document.write( "So, the equation is y=3x-4\r
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\n" ); document.write( "\n" ); document.write( "Now check with a value away from the x=0 value we picked. So, lets pick x=-8.\r
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\n" ); document.write( "\n" ); document.write( "When x=-8, y=3x-4 becomes
\n" ); document.write( "y = 3(-8) -4
\n" ); document.write( "y = -24-4
\n" ); document.write( "y = -28 which is the correct value.\r
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\n" ); document.write( "\n" ); document.write( "So, y=3x-4 is the correct equation of this set of coordinates.\r
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