document.write( "Question 240425: a rectangle has a perimeter of 78 in. its length is 6 in more than twice its length. \n" ); document.write( "
Algebra.Com's Answer #176157 by checkley77(12844)\"\" \"About 
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L=2W+6
\n" ); document.write( "2L+2W=78
\n" ); document.write( "2(2W+6)+2W=78
\n" ); document.write( "4W+12+2W=78
\n" ); document.write( "6W=78-12
\n" ); document.write( "6W=66
\n" ); document.write( "W=66/6
\n" ); document.write( "W=11 ANS.
\n" ); document.write( "L=2*11+6
\n" ); document.write( "L=22+6
\n" ); document.write( "L=28 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*28+2*11=78
\n" ); document.write( "56+22=78
\n" ); document.write( "78=78
\n" ); document.write( "
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