document.write( "Question 240431: if a rectangle has an area of 117cm2 and a perimeter of 44cm what is it's length and breadth \n" ); document.write( "
Algebra.Com's Answer #176152 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
LW=117
\n" ); document.write( "L=117/W
\n" ); document.write( "2L+2W=44
\n" ); document.write( "2(117/W)+2W=44
\n" ); document.write( "234/W+2W=44
\n" ); document.write( "(234+2W^2/W=44
\n" ); document.write( "(234+2W^2)/W=44
\n" ); document.write( "2W^2+234=44W
\n" ); document.write( "2W^2-44W+234=0
\n" ); document.write( "2(W^2-22W+117)=0
\n" ); document.write( "2(W-13)(W-9)=0
\n" ); document.write( "W-13=0
\n" ); document.write( "W=13 ANS.
\n" ); document.write( "L*13=117
\n" ); document.write( "L=117/13
\n" ); document.write( "L=9 ANS
\n" ); document.write( "2*9+2*13=44
\n" ); document.write( "18+26=44
\n" ); document.write( "44=44
\n" ); document.write( "PROOF:\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );