document.write( "Question 240431: if a rectangle has an area of 117cm2 and a perimeter of 44cm what is it's length and breadth \n" ); document.write( "

Algebra.Com's Answer #176143 by stanbon(75887) $\"\"$ $\"About$

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if a rectangle has an area of 117cm2 and a perimeter of 44cm what is it's length and breadth
\n" ); document.write( "------------------------
\n" ); document.write( "width = x
\n" ); document.write( "length = y
\n" ); document.write( "-----------------
\n" ); document.write( "Area = xy = 117 cm^2
\n" ); document.write( "Perim = 2(x+y) = 44 cm
\n" ); document.write( "----------------------------
\n" ); document.write( "x+y = 22
\n" ); document.write( "---------------------
\n" ); document.write( "Solve for y:
\n" ); document.write( "y = 22-x
\n" ); document.write( "-------------------
\n" ); document.write( "Substitute into xy = 117 and solve for \"x\":
\n" ); document.write( "x(22-x) = 117
\n" ); document.write( "-x^2 + 22x - 117 = 0
\n" ); document.write( "x^2 - 22x + 117 = 0
\n" ); document.write( "--------------------
\n" ); document.write( "Quadratic formula:
\n" ); document.write( "x = [22 +- sqrt(22^2 - 4*117)]/2
\n" ); document.write( "x = [22 +- sqrt(16)]/2
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = [11 + 2] = 13 (width)
\n" ); document.write( "-------------------------
\n" ); document.write( "Since x+y = 22, y = 22-13 = 9 (length)
\n" ); document.write( "============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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