document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=240423>Question 240423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am 48, my brother is 42. What is the equation which models how old, in years, I will be when I am 3 times as old as my younger brother. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176130 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am 48, my brother is 42. What is the equation which models how old, in years, I will be when I am 3 times as old as my younger brother.<BR>\n" );
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document.write( "Let the missing years be \"x\".<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "(48+x) = 3(42+x)<BR>\n" );
document.write( "48+x = 126 + 3x<BR>\n" );
document.write( "2x = -78<BR>\n" );
document.write( "x = -39<BR>\n" );
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document.write( "Your age then: 48-39 = 9 <BR>\n" );
document.write( "Your brother's age then: 42-39 = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );