document.write( "Question 240399: The width of a rectangle is 2 m less than half the length. The perimeter is 44 m.Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #176129 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=L/2-2 \n" ); document.write( "2L+2W=44 \n" ); document.write( "2L+2(L/2-2)=44 \n" ); document.write( "2L+L-4=44 \n" ); document.write( "3L=44+4 \n" ); document.write( "3L=48 \n" ); document.write( "L=48/3 \n" ); document.write( "L=16 ANS. FOR THE LENGTH. \n" ); document.write( "W=16/2-2 \n" ); document.write( "W=8-2 \n" ); document.write( "L=6 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*16+2*6=44 \n" ); document.write( "32+12=44 \n" ); document.write( "44=44 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |