document.write( "Question 240399: The width of a rectangle is 2 m less than half the length. The perimeter is 44 m.Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #176129 by checkley77(12844)\"\" \"About 
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W=L/2-2
\n" ); document.write( "2L+2W=44
\n" ); document.write( "2L+2(L/2-2)=44
\n" ); document.write( "2L+L-4=44
\n" ); document.write( "3L=44+4
\n" ); document.write( "3L=48
\n" ); document.write( "L=48/3
\n" ); document.write( "L=16 ANS. FOR THE LENGTH.
\n" ); document.write( "W=16/2-2
\n" ); document.write( "W=8-2
\n" ); document.write( "L=6 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*16+2*6=44
\n" ); document.write( "32+12=44
\n" ); document.write( "44=44 \r
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