document.write( "Question 240385: Normal distribution
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document.write( "A mean amount of profit per car sold for a sample of 25 dealers was 290$, with a standard deviation of 100$ Develop a 90% Confidence interval for th epopulation mean?
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Algebra.Com's Answer #176128 by stanbon(75887) ![]() You can put this solution on YOUR website! Normal distribution \n" ); document.write( "A mean amount of profit per car sold for a sample of 25 dealers was 290$, with a standard deviation of 100$ Develop a 90% Confidence interval for th epopulation mean? \n" ); document.write( "------------- \n" ); document.write( "sample mean: $290 \n" ); document.write( "standard error: 1.645*100/sqrt(25) = 32.9 \n" ); document.write( "--------------------------- \n" ); document.write( "90% CI: 290-32.9 < u < 290+32.9 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |