document.write( "Question 240405: a collection of 81 coins consists of nickels and dinmes only and has a value of $5.80 find the number of nickels and dimes in the collection \n" ); document.write( "
Algebra.Com's Answer #176126 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D+N=81 OR D=81-N \n" ); document.write( ".10D+.05N=5.80 \n" ); document.write( ".10(81-N)+.05N=5.80 \n" ); document.write( "8.10-.10N+.05N=5.80 \n" ); document.write( "-.05N=5.80-8.10 \n" ); document.write( "-.05N=-2.30 \n" ); document.write( "N=-2.30/-.05 \n" ); document.write( "N=46 NICKELS. \n" ); document.write( "D=81-46=35 DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".10*35+.05*46=5.80 \n" ); document.write( "3.50+2.30=5.80 \n" ); document.write( "5.80=5.80 \n" ); document.write( " \n" ); document.write( " |