document.write( "Question 240364: Please help me understand the steps for solving this problem. The value of a two-digit number is twice as large as the sum of its digits. If the digits were reversed, the resulting number would be 9 less than 5 times the original number. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #176124 by scott8148(6628)\"\" \"About 
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let t=\"tens digit\" and u=\"units digit\"\r
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\n" ); document.write( "\n" ); document.write( "\"The value of a two-digit number is twice as large as the sum of its digits\" ___ 10t + u = 2(t + u)
\n" ); document.write( "___ 10t + u = 2t + 2u
\n" ); document.write( "___ 8t = u ___ (there is only one pair of digits that works here)\r
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\n" ); document.write( "\n" ); document.write( "\"If the digits were reversed, the resulting number would be 9 less than 5 times the original number\"
\n" ); document.write( "___ 10u + t = 5(10t + u) - 9
\n" ); document.write( "___ 10u + t = 50t + 5u - 9
\n" ); document.write( "___ 5u + 9 = 49t\r
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\n" ); document.write( "\n" ); document.write( "substitute the value of u from the 1st part to find the value of t
\n" ); document.write( "___ then substitute t back to the 1st part to find the value of u
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