document.write( "Question 240184: I need to solve for x and y by using substitution. I am not sure of how to go about doing this problem. If someone could help I would appreciate it. The problem is:\r
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document.write( "{y=8-3x
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document.write( "{2x-5y=11\r
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document.write( "I know that I need to multiply one problem to make the y's cancel but I am not sure.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #176119 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! I need to solve for x and y by using substitution.\r \n" ); document.write( "\n" ); document.write( " y = 8 - 3x \n" ); document.write( "2x - 5y = 11 \n" ); document.write( ": \n" ); document.write( "Note that y = (8-3x), substitute this for y in the 2nd equation \n" ); document.write( "2x - 5(8-3x) = 11 \n" ); document.write( "Multiply what's inside the brackets, change the signs inside the brackets \n" ); document.write( "2x - 40 + 15x = 11 \n" ); document.write( "2x + 15x = 11 + 40 \n" ); document.write( "17x = 51 \n" ); document.write( "x = \n" ); document.write( "x = 3 \n" ); document.write( ": \n" ); document.write( "Use the 1st equation to find y, substitute 3 for x \n" ); document.write( "y = 8 - 3(3) \n" ); document.write( "y = 8 - 9 \n" ); document.write( "y = -1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions by substitution in the 2nd equation \n" ); document.write( "2x - 5y = 11 \n" ); document.write( "2(3) - 5(-1) = 11 \n" ); document.write( "6 + 5 = 11; confirms our solutions \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "you made the statement,\"I know that I need to multiply one problem to make the y's cancel\" \n" ); document.write( "This is not so in the substitution method. You've got it mixed up with the elimination method. \n" ); document.write( " |