document.write( "Question 240299: x to the 2 power- 3 - 3/4 = 0
\n" ); document.write( "a) solve by completing the square
\n" ); document.write( "b) solve using the quadratic formula\r
\n" ); document.write( "\n" ); document.write( "(x to the 2 power minus x minus three-fourths equal 0.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #176114 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x to the 2 power- 3x - 3/4 = 0
\n" ); document.write( "---
\n" ); document.write( "a) solve by completing the square
\n" ); document.write( "x^2 - 3x - 3/4 = 0
\n" ); document.write( "x^2 - 3x + ? = (3/4)+?
\n" ); document.write( "x^2 - 3x + (3/2)^2 = (3/4) + (3/2)^2
\n" ); document.write( "(x-(3/2))^2 = (3/4) + (9/4)
\n" ); document.write( "(x-(3/2))^2 = 12/4=3
\n" ); document.write( "x-3/2 = sqrt(3) or x-3/2 = -sqrt(3)
\n" ); document.write( "x = (3/2)+sqrt(3) or x = (3/2)-sqrt(3)
\n" ); document.write( "---------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "b) solve using the quadratic formula
\n" ); document.write( "a = 1; b = -3; c = -3/4
\n" ); document.write( "---
\n" ); document.write( "x = [-b +- sqrt(b^2-4ac)]/(2a)
\n" ); document.write( "x = [3 +- sqrt(9 - 4*(-3/4)]/2
\n" ); document.write( "x = [3 +- sqrt(12)]/2
\n" ); document.write( "x = (3/2) + (2/2)sqrt(3) or x = (3/2)-(2/2)sqrt(3)
\n" ); document.write( "x = (3/2)+ sqrt(3) or x = (3/2)-sqrt(3)
\n" ); document.write( "============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );