document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30867>Question 30867</A>: <I><SPAN STYLE=\"word-break: break-all;\">        The problem I have is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+2e%5E%283t-1%29 ALIGN=MIDDLE  ALT=\"y+=+2e%5E%283t-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and i have to make \"t\" the subject.<BR>\n" );
document.write( "I have got to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t+=+%28ln2+-+lny%29%2F3+%2B1 ALIGN=MIDDLE  ALT=\"t+=+%28ln2+-+lny%29%2F3+%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" >. But i doubt very much that is right.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17611 by </B><A HREF=/tutors/aboutme.mpl?userid=acerX><B>acerX(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=acerX><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+2e%5E%283t-1%29 ALIGN=MIDDLE  ALT=\"y+=+2e%5E%283t-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28y%29+=+ln%282e%5E%283t-1%29%29 ALIGN=MIDDLE  ALT=\"ln%28y%29+=+ln%282e%5E%283t-1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  introduce the natural log<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28y%29=+ln%282%29+%2B+ln%28e%5E%283t-1%29%29 ALIGN=MIDDLE  ALT=\"ln%28y%29=+ln%282%29+%2B+ln%28e%5E%283t-1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Product Rule of logs<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28y%29+=+ln%282%29+%2B+%283t-1%29%2Aln%28e%29 ALIGN=MIDDLE  ALT=\"ln%28y%29+=+ln%282%29+%2B+%283t-1%29%2Aln%28e%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Ln of e is 1 as per definition of ln<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28y%29+=+ln%282%29+%2B+3t-1 ALIGN=MIDDLE  ALT=\"ln%28y%29+=+ln%282%29+%2B+3t-1\"   DISABLED_style= \"max-width:90%; height:auto;\" > subtract the ln2 and add the 1 to both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28y%29+-+ln%282%29+%2B1+=+3t ALIGN=MIDDLE  ALT=\"ln%28y%29+-+ln%282%29+%2B1+=+3t\"   DISABLED_style= \"max-width:90%; height:auto;\" > divide both sides by 3 and use the quotient rule of logs<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t+=+%28ln%28y%29+-+ln%282%29+%2B1%29%2F3 ALIGN=MIDDLE  ALT=\"t+=+%28ln%28y%29+-+ln%282%29+%2B1%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So Darryl yes your answer is correct but not in the most simple form </SPAN>\n" );
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