document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=240233>Question 240233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ABCD is a rectangle. Each of the longer sides is 3 cm shorter than twice the shorter side. The perimeter of the rectangle is 24 cm. Find the length of the longer side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176073 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's note down the information we do have first. Lets show the shorter side<BR>\n" );
document.write( "with x and the longer side by 2x-3. Ok, with this we can write an equation as:<BR>\n" );
document.write( "x+x+(2x-3)+(2x-3)=24  Combine like terms. <BR>\n" );
document.write( "6x-6=24  Add 6 to both sides.<BR>\n" );
document.write( "6x=30  Divide both sides by 6<BR>\n" );
document.write( "x=5  So 5 cm is the length of the shorter sides. Plug in 5 to (2x-3) gives us: <BR>\n" );
document.write( "7 cm for the longer sides. <BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
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