document.write( "Question 240207: solve this logarithmic equation & give the exact answer.\r
\n" ); document.write( "\n" ); document.write( "log(base)3 (x+6) + log(base)3 (x-6) - log(base)3 x =2
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Algebra.Com's Answer #176068 by nerdybill(7384)\"\" \"About 
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log(base)3 (x+6) + log(base)3 (x-6) - log(base)3 x =2
\n" ); document.write( "log(base)3 (x+6)(x-6) - log(base)3 x =2
\n" ); document.write( "log(base)3 [(x+6)(x-6)]/x =2
\n" ); document.write( "[(x+6)(x-6)]/x = 3^2
\n" ); document.write( "[(x+6)(x-6)]/x = 9
\n" ); document.write( "(x+6)(x-6) = 9x
\n" ); document.write( "x^2 - 36 = 9x
\n" ); document.write( "x^2 - 9x - 36 = 0
\n" ); document.write( "(x-12)(x+3) = 0
\n" ); document.write( "x = {-3, 12}
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\n" ); document.write( "We can throw out the -3 -- it's an extraneous solution -- leaving us with:
\n" ); document.write( "x = 12\r
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