document.write( "Question 240198: Train A and Train B are traveling in the same direction. Train A is traveling 120 mph, Train B is traveling 150 mph. If train A leaves the station at 2:30am, and Train B leaves the same station at 5:30am, what time will Train B catch up to Train A?\r
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Algebra.Com's Answer #176058 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Train A and Train B are traveling in the same direction. Train A is traveling 120 mph, Train B is traveling 150 mph. If train A leaves the station at 2:30am, and Train B leaves the same station at 5:30am, what time will Train B catch up to Train A? \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "Train A DATA: \n" ); document.write( "rate = 120 mph ; distance = x miles ; time = d/r = x/120 hrs. \n" ); document.write( "------------------------- \n" ); document.write( "Train B DATA: \n" ); document.write( "rate = 150 mph ; distance = x miles ; time = x/150 hrs \n" ); document.write( "------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time A - time B = 3 hrs. \n" ); document.write( "x/120 - x/150 = 3 \n" ); document.write( "(150x - 120x) = 3*120*150 \n" ); document.write( "30x = 360*150 \n" ); document.write( "x = 360*5 \n" ); document.write( "x = 1800 \n" ); document.write( "---------------- \n" ); document.write( "Time for B to catch A: 1800/150 = 12 hrs. \n" ); document.write( "Clock time will be 5:30 PM \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |