document.write( "Question 30781: The question is:
\n" ); document.write( "Determine the vertices, asymptotes, and foci of the hyperbola defined by 144x^2-81y^2=81\r
\n" ); document.write( "\n" ); document.write( "Answers are:
\n" ); document.write( "(A) vertices (0, +1) asymptotes: y=+4/3x, foci (0, +5/4)\r
\n" ); document.write( "\n" ); document.write( "(B) vertices (0, +1) asymptotes: y=+3/4x, foci: (0, +5/4)\r
\n" ); document.write( "\n" ); document.write( "(C) vertices (+3/4,0) asymptotes: y=+3/4x. foci: (+5/4,0)\r
\n" ); document.write( "\n" ); document.write( "(D) vertices (+3/4,0) asymptotes: y=+4/3s, foci: (+5/4,0)]\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help with this.
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Algebra.Com's Answer #17601 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
(144x^2-81y^2=81)(1/81)
\n" ); document.write( "(16/9)(x^2) - y^2 = 1
\n" ); document.write( "(x^2)/(9/16) - y^2 = 1
\n" ); document.write( "horizontal transverse axis
\n" ); document.write( "a=3/4
\n" ); document.write( "b=1
\n" ); document.write( "a^2+b^=c^2
\n" ); document.write( "c=(5/4)
\n" ); document.write( "vertices: (3/4,0);(-3/4,0)
\n" ); document.write( "asymptote: y=(4/3 or -4/3)x
\n" ); document.write( "foci: (5/4,0);(-5/4,0)\r
\n" ); document.write( "\n" ); document.write( "*You are missing some terms*
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