document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=239947>Question 239947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 8:00 am the smiths left a campground driving at 48 mi/hour. At 8:20 the Garcias left the same campground and followed the same route driving at 60 mi/hour. At what time did they overtake the Smiths?\r<BR>\n" );
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document.write( "I thought that I had to take 20/60 to get 1/3, to make minutes into hours, and add it to 60t. Then have 48t equal that. (Shown Below)<BR>\n" );
document.write( "48t = 60(t+1/3)<BR>\n" );
document.write( "Then, I distributed, and got:<BR>\n" );
document.write( "48t = 60t + 20<BR>\n" );
document.write( "I subtracted 60t from 48t, and got this:<BR>\n" );
document.write( "-28t = 20<BR>\n" );
document.write( "I divided 28 by 20, and got 1.4, but I'm not sure if my answer is right. Can you help me?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175959 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you've got the times and speeds reversed\r<BR>\n" );
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document.write( "they overtake when they have travelled the same DISTANCE (rate x time)\r<BR>\n" );
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document.write( "the shorter time goes with the faster speed\r<BR>\n" );
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document.write( "60 t = 48 (t + 1/3) ___ the Smiths had a 20 min head start\r<BR>\n" );
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document.write( "12 t = 16 ___ t = 4/3 or 1:20\r<BR>\n" );
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document.write( "8:20 + 1:20 = 9:40 </SPAN>\n" );
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