document.write( "Question 239836: a man is now four times as old as his son and in four years from now, the product of their ages will be 520. Find their ages now. \n" ); document.write( "
Algebra.Com's Answer #175896 by checkley77(12844) ![]() You can put this solution on YOUR website! LET THE MAN'S AGE=4X \n" ); document.write( "LET THE SON'S AGE-X \n" ); document.write( "(4X+4)(X+4)=520 \n" ); document.write( "4X^2+4X+16X+16=520 \n" ); document.write( "4X^2+20X+16-520=0 \n" ); document.write( "4X^2+20X-504=0 \n" ); document.write( "4(X^2+5X-126)=0 \n" ); document.write( "4(X-9)(X+14)=0 \n" ); document.write( "X-9=0 \n" ); document.write( "X=9 AGE OF THE SON. \n" ); document.write( "4*9=36 AGE OF THE DAD. \n" ); document.write( "PROOF: \n" ); document.write( "(4*9+4)(9+4)=520 \n" ); document.write( "(36+4)(13)=520 \n" ); document.write( "40*13=520 \n" ); document.write( " \n" ); document.write( " |