document.write( "Question 239836: a man is now four times as old as his son and in four years from now, the product of their ages will be 520. Find their ages now. \n" ); document.write( "
Algebra.Com's Answer #175896 by checkley77(12844)\"\" \"About 
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LET THE MAN'S AGE=4X
\n" ); document.write( "LET THE SON'S AGE-X
\n" ); document.write( "(4X+4)(X+4)=520
\n" ); document.write( "4X^2+4X+16X+16=520
\n" ); document.write( "4X^2+20X+16-520=0
\n" ); document.write( "4X^2+20X-504=0
\n" ); document.write( "4(X^2+5X-126)=0
\n" ); document.write( "4(X-9)(X+14)=0
\n" ); document.write( "X-9=0
\n" ); document.write( "X=9 AGE OF THE SON.
\n" ); document.write( "4*9=36 AGE OF THE DAD.
\n" ); document.write( "PROOF:
\n" ); document.write( "(4*9+4)(9+4)=520
\n" ); document.write( "(36+4)(13)=520
\n" ); document.write( "40*13=520
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