document.write( "Question 239806: 2 logx= log(8x-160)+1 \n" ); document.write( "

Algebra.Com's Answer #175890 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2+logx=+log%28%288x-160%29%29%2B1\"$
\n" ); document.write( " $\"logx%5E2=+log%28%288x-160%29%29%2B1\"$
\n" ); document.write( " $\"logx%5E2+-+log%28%288x-160%29%29=+1\"$
\n" ); document.write( " $\"log%28%28x%5E2%2F%288x-160%29%29%29+=+1\"$
\n" ); document.write( " $\"x%5E2%2F%288x-160%29+=+10%5E1\"$
\n" ); document.write( " $\"x%5E2+%2F%288x-160%29+=+10\"$
\n" ); document.write( " $\"x%5E2+=+80x+-+1600\"$
\n" ); document.write( " $\"x%5E2+-+80x+%2B+1600=0\"$
\n" ); document.write( "(((x-40)(x-40)=0}}}
\n" ); document.write( "x=40\r
\n" ); document.write( "\n" ); document.write( "Check your answer with a calculator. Does 2 log(40) = log(320-160) + 1 ???\r
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\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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