document.write( "Question 239705: PLEASE, PLEASE HELP ME!!!\r
\n" ); document.write( "\n" ); document.write( "Given \"+5x%5E4+-+3x%5E3+%2B+ax%5E2+%2B+bx+-+7+=+0+\" determine a and b so that i is a zero of the quartic.\r
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Algebra.Com's Answer #175873 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
5x^4 - 3x^3 + ax^2 + bx - 7 = 0
\n" ); document.write( "f(i)=5-3(-i)-a+bi-7=0
\n" ); document.write( "-3(-i)-a+bi=2 because 5-7=-2
\n" ); document.write( "-3(-i)+bi=2+a
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\n" ); document.write( "f(-i)=5-3i-a+b(-i)-7=0 If one zero is i then another must be -i.
\n" ); document.write( "-3i-a+b(-i)=2
\n" ); document.write( "-3i+b(-i)=2+a
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\n" ); document.write( "-3(-i)+bi=-3i+b(-i) Since they both equal 2+a.
\n" ); document.write( "-3-b=3+b multiply each side by i.
\n" ); document.write( "2b=-6
\n" ); document.write( "b=-3
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\n" ); document.write( "a=-3(-i)-3i-2
\n" ); document.write( "a=-2
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\n" ); document.write( "It checks.
\n" ); document.write( "This WAS tough!
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\n" ); document.write( "Ed
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