document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=239709>Question 239709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3s squared +2 = -62 \r<BR>\n" );
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document.write( "I subtracted 2 so that 3s squared = -60 and divided -60 by 3, giving me -20.  I then had s squared = -20 and, since you can't have negative square roots, i put S= + or - 2 root 5, but im not sure if that is right.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175871 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3s^2+2=-62<BR>\n" );
document.write( "3s^2=-64<BR>\n" );
document.write( "s^2=-64/3<BR>\n" );
document.write( "s=+-8sqrt(-1/3)<BR>\n" );
document.write( "=8sqrt(1/3)i [i=sqrt(-1)]<BR>\n" );
document.write( "sqrt(1/3)=1/sqrt(3)=1/sqrt(3) * sqrt(3)/sqrt(3) = sqrt(3)/3 no sqrt in denominator.<BR>\n" );
document.write( "s=8sqrt(3)i/3, s=-8sqrt(3)i/3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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