document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=239621>Question 239621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 16 more than the other. Decreasing the smaller number by 6 and multiplying by 3 will result in the larger number. Find the product of the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175831 by </B><A HREF=/tutors/aboutme.mpl?userid=College+Student><B>College Student(505)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=College+Student><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=College+Student><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If one number is \"x\", the other is \"x+16\".<BR>\n" );
document.write( "The equationaccording to the problem would be:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%28x-6%29=%28x%2B16%29 ALIGN=MIDDLE  ALT=\"3%28x-6%29=%28x%2B16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You now need to workout the algebra to solve for x.  Your other number would be x+16. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );