document.write( "Question 30833: There is a box with a square base, and a volume of 32000cm^3, with an open top, what is the least material used, and what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #17583 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let a side of the square base = x \n" ); document.write( "Let the height of the box = y \n" ); document.write( "The volume, V = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The dimensions of the materials = 4*x*y for the sides \n" ); document.write( "and x^2 for the base \n" ); document.write( "M = materials \n" ); document.write( " \n" ); document.write( "from above \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "find M'= MP the dirivative of M \n" ); document.write( " \n" ); document.write( "set MP = 0 to find a minimum \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply both sides by x^2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The base is 40X40 cm \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The height is 20 cm\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |