document.write( "Question 239567: 40 grams of a 50% acid solution. How much water must be added to make a 10% solution \n" ); document.write( "
Algebra.Com's Answer #175791 by checkley77(12844)\"\" \"About 
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.50*40=.10(40+x)
\n" ); document.write( "20=4+.10x
\n" ); document.write( ".10x=20-4
\n" ); document.write( ".10x=16
\n" ); document.write( "x=16/.10
\n" ); document.write( "x=160 grams of water is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".50*40=.10(40+160)
\n" ); document.write( "20=.10*200
\n" ); document.write( "20=20
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