document.write( "Question 239286: The length of a room is 5 less than twice the width. The perimeter is 80 feet. \n" ); document.write( "
Algebra.Com's Answer #175703 by anantha(86)\"\" \"About 
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sol:
\n" ); document.write( "let width be x
\n" ); document.write( "twice the width=2x
\n" ); document.write( "length of the room=5 less than twice the width=2x-5
\n" ); document.write( "perimeter of the rectangle=2*(length+width)=2*(2x-5+x)=2*(3x-5)
\n" ); document.write( "according to the problem perimeter of the rectangle=80 feet
\n" ); document.write( "2*(3x-5)=80
\n" ); document.write( "dividing both sides by 2
\n" ); document.write( "2*(3x-5)/2=80/2
\n" ); document.write( "3x-5=40
\n" ); document.write( "adding both sides by 5
\n" ); document.write( "3x-5+5=40+5
\n" ); document.write( "3x=45
\n" ); document.write( "dividing by 3 on both sides
\n" ); document.write( "3x/3=45/3
\n" ); document.write( "x=15
\n" ); document.write( "width=15 feet
\n" ); document.write( "and length=2x-5=(2*15)-5=30-5=25 feet
\n" ); document.write( "check this problem:
\n" ); document.write( "perimeter =2*(length+width)=2(25+15)=2*40=80 feet
\n" ); document.write( "which is given
\n" ); document.write( " \n" ); document.write( "
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