document.write( "Question 239265: RAIN-GUTTER DESIGN: An open rectangle gutter is made by turning up the sides of a piece of metal 20 in. wide. The area of the cross- section of the gutter is 50 in^2. Can you please help me find the depth. \n" ); document.write( "
Algebra.Com's Answer #175696 by ankor@dixie-net.com(22740)\"\" \"About 
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RAIN-GUTTER DESIGN: An open rectangle gutter is made by turning up the sides of a piece of metal 20 in. wide.
\n" ); document.write( " The area of the cross- section of the gutter is 50 in^2.
\n" ); document.write( ":
\n" ); document.write( "Let d = the depth
\n" ); document.write( "Let w = the width of the gutter
\n" ); document.write( ":
\n" ); document.write( "d|__|d would be a picture of the end of it, the horizontal line is the width (w)
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\n" ); document.write( "the piece of metal is 20\" wide, therefore:
\n" ); document.write( "2d + w = 20
\n" ); document.write( "w = (20-2d)
\n" ); document.write( ":
\n" ); document.write( "The area = depth * width
\n" ); document.write( "d * w = 50
\n" ); document.write( ":
\n" ); document.write( "Replace w with (20-2d)
\n" ); document.write( "d(20-2d) = 50
\n" ); document.write( "-2d^2 + 20d - 50 = 0; our old friend, the quadratic equation!
\n" ); document.write( ":
\n" ); document.write( "Simplify and change the signs, divide by -2
\n" ); document.write( "d^2 - 10d + 25 = 0
\n" ); document.write( ":
\n" ); document.write( "Factors easily to:
\n" ); document.write( "(d - 5)(d - 5) = 0
\n" ); document.write( "d = 5 inches is the depth
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\n" ); document.write( "Lets see if this is true
\n" ); document.write( "w = 20 - 2d
\n" ); document.write( "w = 20 - 10
\n" ); document.write( "w = 10 inches is the width
\n" ); document.write( ":
\n" ); document.write( "Check the area 5 * 10 = 50
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\n" ); document.write( "Did this make sense to you? Did I explain it well enough for you to understand?
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