document.write( "Question 239224: In 1993, the life expectancy of males in a certain country was 66.3 years. In 1997, it was 69.6 years. Let E represent the life expectancy in year t and let t represent the number of years since 1993.\r
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document.write( "The linear function E(t) that fits this data is?
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document.write( "E(t)=_t+_\r
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document.write( "Use the function to predict the life expectancy of males in 2004.
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document.write( "E(11)=_ \n" );
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Algebra.Com's Answer #175693 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In 1993, the life expectancy of males in a certain country was 66.3 years. In 1997, it was 69.6 years. Let E represent the life expectancy in year t and let t represent the number of years since 1993. \n" ); document.write( "The linear function E(t) that fits this data is \n" ); document.write( "E(t)=_t+_ \n" ); document.write( ": \n" ); document.write( "Find the slope \n" ); document.write( "In 1993; t1=0 and E1=66,3 \n" ); document.write( "In 1997; t2=4 and E2=69.6 \n" ); document.write( ": \n" ); document.write( "Find the slope (m) using the slope equation: m = \n" ); document.write( "m = \n" ); document.write( "therefore: \n" ); document.write( "The Linear function E(t) that fits the data is. \n" ); document.write( "E(t)= .825t + 66.3 \n" ); document.write( ": \n" ); document.write( "Use the Function to predict the life expectancy of males in 2004. \n" ); document.write( "This means t=11; substitute 11 for t in the equation \n" ); document.write( ": \n" ); document.write( "E(11)= .825(11) + 66.3 \n" ); document.write( "E(11)= 9.075 + 66.3 \n" ); document.write( "E(11)= 75.4 yrs is the life expectancy in 2004 \n" ); document.write( "Rounded to the nearest tenth.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |