document.write( "Question 239245: There are 15 coins consisting of nickels, dimes and quarters. Their total is $1.10. The is one less nickels than four times the dimes. How many of each coin are there? Equation needed. \n" ); document.write( "
Algebra.Com's Answer #175687 by josmiceli(19441)\"\" \"About 
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Let \"n\" = number of nickels
\n" ); document.write( "Let \"d\" = number of dimes
\n" ); document.write( "Let \"q\" = number of quarters
\n" ); document.write( "given:
\n" ); document.write( "(1) \"5n+%2B+10d+%2B+25q+=+110\" (in cents)
\n" ); document.write( "(2) \"n+=+4d+-+1\"
\n" ); document.write( "There are 3 unknowns, and only 2 equations,
\n" ); document.write( "so it will take some extra work to solve
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( " \"5%2A%284d+-+1%29+%2B+10d+%2B+25q+=+110\"
\n" ); document.write( "\"20d+-+5+%2B+10d+%2B+25q+=+110\"
\n" ); document.write( "\"30d+%2B+25q+=+115\" cents
\n" ); document.write( "Now just use logic
\n" ); document.write( "There can't be 5 quarters, since that's more than \"115\"
\n" ); document.write( "There can't be 4 quarters, since
\n" ); document.write( "\"30d+%2B+25%2A4+=+115\"
\n" ); document.write( "\"30d+%2B+100+=+115\"
\n" ); document.write( "\"30d+=+15\"
\n" ); document.write( "\"d+=+1%2F2\" (can't have 1/2 dime)
\n" ); document.write( "I'll try 3 quarters
\n" ); document.write( "\"30d+%2B+25%2A3+=+115\"
\n" ); document.write( "\"30d+=+115+-+75\"
\n" ); document.write( "\"30d+=+40\"
\n" ); document.write( "\"d+=+4%2F3\" (can't have 4/3 dimes)
\n" ); document.write( "I'll try 2 quarters
\n" ); document.write( "\"30d+%2B+25%2A2+=+115\"
\n" ); document.write( "\"30d+=+115+-+50\"
\n" ); document.write( "\"30d+=+65\"
\n" ); document.write( "\"d+=+13%2F6\" (can't have 13/6 dimes)
\n" ); document.write( "And 1 quarter
\n" ); document.write( "\"30d+%2B+25%2A1+=+115\"
\n" ); document.write( "\"30d+=+90\"
\n" ); document.write( "\"d+=+3\"
\n" ); document.write( "and, since
\n" ); document.write( "(2) \"n+=+4d+-+1\"
\n" ); document.write( "\"n+=+4%2A3+-+1\"
\n" ); document.write( "\"n+=+11\"
\n" ); document.write( "There is 1 quarter, 3 dimes, and 11 nickels
\n" ); document.write( "check:
\n" ); document.write( "(1) \"5n+%2B+10d+%2B+25q+=+110\"
\n" ); document.write( "\"5%2A11+%2B+10%2A3+%2B+25%2A1+=+110\"
\n" ); document.write( "\"55+%2B+30+%2B+25+=+110\"
\n" ); document.write( "\"110+=+110\"
\n" ); document.write( "OK
\n" ); document.write( "
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