document.write( "Question 239139: Mixture A is 7.5% acid. To raise the concentration of acid to 10%, some pure acid will be added to the mixture. How many liters of mixture A and how many liters of pure acid are needed to end up with 200 liters of 10% solution? \n" ); document.write( "
Algebra.Com's Answer #175686 by ankor@dixie-net.com(22740)\"\" \"About 
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Mixture A is 7.5% acid. To raise the concentration of acid to 10%, some pure acid will be added to the mixture.
\n" ); document.write( " How many liters of mixture A and how many liters of pure acid are needed to end up with 200 liters of 10% solution?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of pure acid required,
\n" ); document.write( "It says the total has to be 200 liters, therefore
\n" ); document.write( "(200-x) = 7.5% stuff (A)
\n" ); document.write( ":
\n" ); document.write( "1.0x + .075(200-x) = .10(200)
\n" ); document.write( ":
\n" ); document.write( "x + 15 - .075x = 20
\n" ); document.write( ":
\n" ); document.write( "x - .075x = 20 - 15
\n" ); document.write( ":
\n" ); document.write( ".925x = 5
\n" ); document.write( "x = \"5%2F.925\"
\n" ); document.write( "x = 5.4 liters of pure acid require
\n" ); document.write( "then
\n" ); document.write( "200 - 5.4 = 194.6 liters of 7.5% stuff (A)
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\n" ); document.write( ":
\n" ); document.write( "Check solution in original equaiton
\n" ); document.write( "5.4 + .075(194.6) = .10(200)
\n" ); document.write( "5.4 + 14.6 = 20
\n" ); document.write( " \n" ); document.write( "
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