document.write( "Question 239150: Can someone please help me? ----- (elimination method)\r
\n" ); document.write( "\n" ); document.write( "The assignment is on the elimination method - and I don't understand why it is not coming out evenly.\r
\n" ); document.write( "\n" ); document.write( "2/3x+y=-5/3 and x-1/3y=-13/3
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Algebra.Com's Answer #175654 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
2/3x+y=-5/3 multiply this equation by 1/3 & add.
\n" ); document.write( "x-y/3=-13/3
\n" ); document.write( "2x/9+y/3=-5/9
\n" ); document.write( "------------------
\n" ); document.write( "x+2x/9=-13/3-5/9
\n" ); document.write( "(9x+2x)/9=(-13*3-5)/9 cancel out the denominators.
\n" ); document.write( "11x=-39-5
\n" ); document.write( "11x=-44
\n" ); document.write( "x=-44/11
\n" ); document.write( "x=-4 ans.
\n" ); document.write( "-4-y/3=-13/3
\n" ); document.write( "-y/3=-13/3+4
\n" ); document.write( "-y/3=(-13+4*3)/3 cancel out the denominators.13+12
\n" ); document.write( "-y=-1
\n" ); document.write( "y=1 ans.
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