document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=239166>Question 239166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> wendy has 52 coins consisting of nickels and pennies. If the value of the coins is $1.20 then how many of each coin type does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175653 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let N = Number of Nickel Coins<BR>\n" );
document.write( "    P = Number of Pennie Coins\r<BR>\n" );
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document.write( "$0.05N+$0.01P = $1.20\r<BR>\n" );
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document.write( "We know that N+P=52\r<BR>\n" );
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document.write( "Rearranging we get P=52-N\r<BR>\n" );
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document.write( "So subsituting in gives $0.05N+$0.01(52-N) = $1.20\r<BR>\n" );
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document.write( "$0.05N+$0.52-$0.01N = $1.20<BR>\n" );
document.write( "$0.04N+$0.52 = $1.20<BR>\n" );
document.write( "$0.04N = $1.20 - $0.52<BR>\n" );
document.write( "N = $0.68/$0.04<BR>\n" );
document.write( "N = 17<BR>\n" );
document.write( "So P = 35\r<BR>\n" );
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document.write( "Does that makes sense?\r<BR>\n" );
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document.write( " </SPAN>\n" );
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