document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=239157>Question 239157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve using linear combination's 2x-y=8 and x+y=1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175649 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how to solve using linear combination's <BR>\n" );
document.write( "2x-y=8 <BR>\n" );
document.write( " x+y=1<BR>\n" );
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document.write( "Multiply thru the 2nd equation by 2 to get:<BR>\n" );
document.write( "2x-y = 8<BR>\n" );
document.write( "2x+2y = 2<BR>\n" );
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document.write( "Subtract the 1st from the 2nd Eq:<BR>\n" );
document.write( "3y = -6<BR>\n" );
document.write( "y = -2<BR>\n" );
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document.write( "Substitute into x+y = 1 to solve for \"x\":<BR>\n" );
document.write( "x + -2 = 1<BR>\n" );
document.write( "x = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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