document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=239043>Question 239043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok i really need help on this problem. i am in honors algebra 2 and i dont know what to do. Please help me solve the word problem: A  rectangle  is  3  times  as  long  as  it  is  wide.  If  the  length  and  the  width  are  both  decreased  by  4  cm,  the  resulting  rectangle  has  area  28cm  squared.  Find  the  dimensions  of  the  original  rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175613 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A  rectangle  is  3  times  as  long  as  it  is  wide.  If  the  length  and  the  width  are  both  decreased  by  4  cm,  the  resulting  rectangle  has  area  28cm  squared.  Find  the  dimensions  of  the  original  rectangle.\r<BR>\n" );
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document.write( "L = 3W\r<BR>\n" );
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document.write( "(L-4) * (W-4) = 28\r<BR>\n" );
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document.write( "Replace L with 3W to get:\r<BR>\n" );
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document.write( "(3W-4) * (W-4) = 28\r<BR>\n" );
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document.write( "remove parentheses by multiplying out the factors to get:\r<BR>\n" );
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document.write( "3W^2 - 16W + 16 = 28\r<BR>\n" );
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document.write( "subtract 28 from both sides to get:\r<BR>\n" );
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document.write( "3W^2 - 16W - 12 = 0\r<BR>\n" );
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document.write( "this factors out to:\r<BR>\n" );
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document.write( "(3W+2) * (W-6) = 0\r<BR>\n" );
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document.write( "This makes 3W = -2 or W = 6\r<BR>\n" );
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document.write( "W can't be negative so W = 6 is the only valid answer.\r<BR>\n" );
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document.write( "if W = 6, then L = 3W makes L = 18\r<BR>\n" );
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document.write( "You have L = 18 and W = 6\r<BR>\n" );
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document.write( "substitute in the original equation to get:\r<BR>\n" );
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document.write( "(L-4) * (W-4) = 28 becomes:\r<BR>\n" );
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document.write( "(18-4) * (6-4) = 28 which becomes:\r<BR>\n" );
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document.write( "14 * 2 = 28 which becomes:\r<BR>\n" );
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document.write( "28 = 28 which is true so the values for L and W must be good.\r<BR>\n" );
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document.write( "Your answers are:\r<BR>\n" );
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document.write( "L = 18 and W = 6\r<BR>\n" );
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document.write( " </SPAN>\n" );
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