document.write( "Question 239020: Find the center and the radius of the circle x+1 squared + y+4 squared =81. \n" ); document.write( "
Algebra.Com's Answer #175602 by Theo(13342)![]() ![]() You can put this solution on YOUR website! (x+1)^2 + (y+4)^2 = 81\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the center of this circle should be at (x,y) = (-1,-4).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Graph of your equation seems to confirm that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order to graph, you need to solve for y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the solved equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = -4 +/- sqrt(81-(x+1)^2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It looks like your original equation is in the form of (x-h)^2 + (y-k)^2 = r^2 where:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h = x coordinate of the center of the circle. \n" ); document.write( "k = y coordinate of the center of the circle. \n" ); document.write( "r = the radius of the circle. \n" ); document.write( " \n" ); document.write( " |