document.write( "Question 239077: please help me slove this question . \r
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\n" ); document.write( "\n" ); document.write( "the question : Measurement: use the form C= 5 on 9(f-32) to transform Temperatures from celicios (C) to fahrenheit (F) . write the transformation form from fahrenheit to celicios ?
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Algebra.Com's Answer #175594 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
formulas are:\r
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\n" ); document.write( "\n" ); document.write( "F = (9/5)*C + 32\r
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\n" ); document.write( "\n" ); document.write( "C = (F-32)*(5/9)\r
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\n" ); document.write( "\n" ); document.write( "If C = 0, then F = 32\r
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\n" ); document.write( "\n" ); document.write( "If C = 100, then F = 212\r
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\n" ); document.write( "\n" ); document.write( "Going from C to F is ok.\r
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\n" ); document.write( "\n" ); document.write( "If F = 32, C = 0\r
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\n" ); document.write( "\n" ); document.write( "If F = 212, C = 100\r
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\n" ); document.write( "\n" ); document.write( "Going from F to C is ok.\r
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\n" ); document.write( "\n" ); document.write( "If C = 5, then F = (9/5)*C + 32 = 9 + 32 = 41 degrees farenheit.\r
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\n" ); document.write( "\n" ); document.write( "If F = 41, then C = (F-32)*(5/9) = (41-32)*(5/9) = 9*(5/9) = 5 degrees Celsius.\r
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