document.write( "Question 239035: Can you help with this word problem please?\r
\n" ); document.write( "\n" ); document.write( "Rachel allows herself 1 hour to reach a sales appointment 50 miles away. After she has driven 30 miles, she realizes that she must increase her speed by 15mph in order to get there on time. What was her speed for the first 30 miles?
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Algebra.Com's Answer #175577 by stanbon(75887)\"\" \"About 
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Rachel allows herself 1 hour to reach a sales appointment 50 miles away. After she has driven 30 miles, she realizes that she must increase her speed by 15mph in order to get there on time. What was her speed for the first 30 miles?
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\n" ); document.write( "1st leg DATA:
\n" ); document.write( "distance = 30 miles ; rate = x mph ; time = d/r = 30/x hrs
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\n" ); document.write( "2nd leg DATA:
\n" ); document.write( "distance = 20 miles ; rate = x+15 mph ; time = d/r = 20/(x+15) hrs.
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 1 hr
\n" ); document.write( "30/x + 20/(x+15) = 1
\n" ); document.write( "30(x+15) + 20x = x(x+15)
\n" ); document.write( "x^2 +15x = 50x + 450 = 0
\n" ); document.write( "x^2 - 35x - 450 = 0
\n" ); document.write( "x = 45 mph (her rate for the first 30 miles)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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