document.write( "Question 30820: waht is the answer to this problem 2r-s=1 and 3r+2s=19
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Algebra.Com's Answer #17556 by Nate(3500) $\"\"$ $\"About$

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2r-s=1
\n" ); document.write( "and
\n" ); document.write( "3r+2s=19
\n" ); document.write( "First, get s by itself
\n" ); document.write( "2r-s=1
\n" ); document.write( "-s=-2r+1
\n" ); document.write( "s=2r-1
\n" ); document.write( "plug 2r-1 for s in the other equation
\n" ); document.write( "3r+2s=19
\n" ); document.write( "3r+2(2r-1)=19
\n" ); document.write( "3r+4r-2=19
\n" ); document.write( "7r=21
\n" ); document.write( "r=3
\n" ); document.write( "plug in r in one of the equations
\n" ); document.write( "2r-s=1
\n" ); document.write( "6-s=1
\n" ); document.write( "-s=-5
\n" ); document.write( "s=5 \n" ); document.write( "

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