document.write( "Question 237935: Please help.
\n" ); document.write( "Express using a positive exponent
\n" ); document.write( "t^-2\r
\n" ); document.write( "\n" ); document.write( "Solve solution set
\n" ); document.write( "(x+5)(x-11)(x+4)>0
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Algebra.Com's Answer #175512 by College Student(505)\"\" \"About 
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Express using a positive exponent: \"t%5E-2\"
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\n" ); document.write( "Negative exponents signify fractions. So we can re-write this term as \"1%2Ft%5E2\". This would give you the positive exponent you're looking for.
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\n" ); document.write( "Solve solution set:
\n" ); document.write( "(x+5)(x-11)(x+4)>0
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\n" ); document.write( "We know that any number multiplied by zero equals zero, right?
\n" ); document.write( "So, since the inequality tells us the left side must be greater than zero, none of the three terms can equal to zero.
\n" ); document.write( "Can you see why? Because if any of them do, we would end up with 0>0... which would be wrong.
\n" ); document.write( "So now we look for valid values in each term.
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\n" ); document.write( "\"x%2B5\" must be greater than zero, so x must be any number greater or equal to 6
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\n" ); document.write( "\"%28x-11%29\" must also be greater than zero, so x must be any number greater or equal to 12
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\n" ); document.write( "\"%28x%2B4%29\" must aslo be greater than zero, so x must be any number greater or equal to 5
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\n" ); document.write( "Solution set: x>=6, >=12, >=5
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