document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30816>Question 30816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A collection of jewelry includes two rings, one is 18 years old and the other 46 years old.  In how many years will the older ring be twice as old as the newer ring? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17551 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the future age be x<BR>\n" );
document.write( "18+x<BR>\n" );
document.write( "46+x\r<BR>\n" );
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document.write( "2(18+x)=46+x<BR>\n" );
document.write( "36+2x=46<BR>\n" );
document.write( "x=10\r<BR>\n" );
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document.write( "Hence, in two years it will be twice as old.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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