document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=238842>Question 238842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists, 95 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 4 hr later, at what average speed is each cyclist traveling? (Round the answers to two decimal places.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175488 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "95=(X+2X)4<BR>\n" );
document.write( "95=3X*4<BR>\n" );
document.write( "95=12X<BR>\n" );
document.write( "X=95/12<BR>\n" );
document.write( "X=7.91 MPH IS THE SLOWER SPEED RIDER.<BR>\n" );
document.write( "2*7.91=15.83 MPH FOR THE FASTER RIDER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "95=(7.91+15.83)4<BR>\n" );
document.write( "95=23.74*4<BR>\n" );
document.write( "95~95\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );